Electrochemistry (ISC Class 12): The Complete Chapter 2 Guide with Formulas, Exam Traps and Practice Questions

Electrochemistry is one of those chapters that ISC Class 12 students either love or quietly dread. There is no middle ground. The reason is simple: it sits at the junction of physical chemistry’s two most demanding skills—conceptual clarity about what happens inside a cell, and numerical accuracy in applying formulas that all look deceptively similar.

The good news is that the entire chapter is built on a very small number of ideas. Once you see how conductance, electrode potential, the Nernst equation and free energy are all describing the same story from different angles, the numericals stop being a memory test and start being obvious.

This guide walks through the whole of Chapter 2: Electrochemistry in the order it should be understood — not the order it is usually crammed. It is aligned with the ISC Chemistry (Class XII) syllabus for the Examination Year 2027.

What this guide covers

  1. What Electrochemistry Actually Studies
  2. Conductance: What Makes a Solution Conduct Well?
  3. Conductivity, Cell Constant and the Two Conductivities
  4. Faraday’s Laws of Electrolysis
  5. Galvanic Cells, Salt Bridge and Cell Notation
  6. Electrode Potential and the SHE
  7. The Electrochemical Series
  8. Cell Potential, EMF and Potential Difference
  9. The Nernst Equation
  10. Equilibrium Constant and Gibbs Free Energy
  11. Variation of Molar Conductivity with Concentration
  12. Kohlrausch’s Law
  13. Batteries and Fuel Cells
  14. Corrosion
  15. Ten Mistakes That Cost Marks
  16. Quick Formula Revision Sheet
  17. Test Yourself
  18. Frequently Asked Questions

1. Start Here: What Electrochemistry Actually Studies

Electrochemistry is the branch of chemistry that examines the relationship between electrical energy and the chemical changes in a redox reaction.

That relationship runs in two directions, and those two directions give us the two types of cells the entire chapter revolves around.

Electrochemical (Galvanic / Voltaic) Cell Electrolytic Cell
Energy conversion Chemical → Electrical Electrical → Chemical
Nature of reaction Spontaneous redox reaction Non-spontaneous redox reaction
Driving force The reaction itself produces current External current forces the reaction
Sign of ΔG Negative Positive
Anode Negative terminal Positive terminal
Cathode Positive terminal Negative terminal
In both cases, remember where the current actually flows: ions move through the solution in the inner circuit, and electrons move through the wire in the external circuit. Electrons never travel through the solution. This single sentence quietly prevents about half the conceptual errors students make in this chapter.

2. Conductance: What Makes a Solution Conduct Well?

Before touching any formula, understand the three interactions that decide how easily ions move.

(a) Solute–solute interactions (interionic attraction). Dissociated ions attract each other because of opposite charges. The stronger this pull, the harder it is for ions to move. This is the basis on which electrolytes are classified as strong or weak.

(b) Solute–solvent interactions (solvation). Solvent molecules surround the ions, keeping them apart and preventing recombination.

(c) Solvent–solvent interactions (viscosity). A more viscous solvent physically restricts ionic movement.

All three of these resisting effects weaken as temperature rises. Hence:

Electrolytic conduction increases with a rise in temperature. Metallic conduction decreases. That opposite behaviour is a favourite one-mark question.

The four factors, stated the way examiners want them

  • Nature of the electrolyte — strong electrolytes ionise almost completely and conduct much better than weak electrolytes.
  • Nature of the solvent — the greater the polarity of the solvent, the greater the ionisation, and hence the greater the conduction.
  • Concentration — higher concentration means stronger interionic attraction and lower conduction. On dilution, conduction increases.
  • Temperature — higher temperature increases dissociation and ionic mobility, so conduction increases.

Metallic vs Electrolytic Conductance

Feature Metallic Conductance Electrolytic Conductance
Carrier of current Free electrons in a fixed metal lattice Ions moving through the solution
Transfer of matter None Yes — ions deposited or liberated at electrodes
Effect of temperature Decreases (lattice vibrations hinder electrons) Increases (more ionisation and mobility)
Chemical change None in the conductor Always — oxidation at anode, reduction at cathode

3. Conductivity, Cell Constant and the Two “Conductivities”

Resistance of a conductor is directly proportional to length and inversely proportional to area of cross-section:

R = ρ × l / A

Here ρ (rho) is the resistivity or specific resistance — a constant for a given material. A 10 cm copper wire and a 20 cm copper wire have exactly the same resistivity.

Its reciprocal is conductivity (specific conductivity), denoted by κ (kappa):

κ = 1 / ρ = G × (l / A)

The term l / A is fixed for a given conductivity cell and is called the cell constant (unit: cm–1).

If l = 1 cm and A = 1 cm2, then κ = G. So:

Conductivity of a solution is the conductance of a solution of one centimeter length having one square centimeter area of cross-section.

Equivalent and molar conductivity

Equivalent conductivity (Λeq) is the conductance of all the ions produced from one gram equivalent of electrolyte dissolved in V cm3 of solution, with the electrodes 1 cm apart and large enough to contain the whole solution.

Λeq = κ × V = κ × 1000 / Normality

Molar conductivity (Λm) is the same idea, but for one mole of electrolyte:

Λm = κ × V = κ × 1000 / Molarity

The units table you must not confuse

Quantity Symbol Unit
Resistivity ρ ohm cm
Conductivity κ ohm–1 cm–1 or S cm–1
Cell constant l / A cm–1
Equivalent conductivity Λeq ohm–1 cm2 (g eq)–1 or S cm2 (g eq)–1
Molar conductivity Λm ohm–1 cm2 mol–1 or S cm2 mol–1
The 1000 in those formulas is not decoration — it converts liters to cm3. Drop it, and your answer is off by three orders of magnitude, which is the single most common numerical error in this chapter.

4. Faraday’s Laws of Electrolysis

First Law

The mass of any substance deposited or liberated at any electrode is directly proportional to the quantity of electricity passed.

W ∝ Q, or W = ZQ = Z × I × t

Z is the electrochemical equivalent — the mass deposited when one coulomb of electricity is passed (i.e., 1 ampere for 1 second).

Z = Equivalent weight of the substance / 96500

Second Law

When the same quantity of electricity is passed through solutions of different electrolytes taken in separate cells connected in series, the weights of the substances produced at the electrodes are directly proportional to their equivalent weights.
WCu / WAg = Eq. wt. of Cu / Eq. wt. of Ag

Where 96500 comes from

Consider the electrolysis of molten NaCl: Na+ + e → Na. One electron produces one atom of sodium, so one mole of electrons produces one mole of sodium.

Charge on one mole of electrons = (1.6023 × 10–19 C) × (6.023 × 1023 mol–1) = 96490 C mol–1 ≈ 96500 C mol–1

This is one faraday (F). So 1 F deposits 1/n mole = one gram equivalent of a substance, where n is the number of electrons involved in the electrode reaction.

5. Galvanic Cells, Salt Bridge and Cell Notation

A voltaic cell has two half-cells. Oxidation happens at the anode; reduction at the cathode. Two mnemonics worth keeping:

“An Ox”Anode = Oxidation   |   “Red Cat”Reduction = Cathode

Functions of the salt bridge

  1. To complete the electrical circuit by allowing ions to flow without the two solutions mixing.
  2. To maintain the electrical neutrality of the solutions in the two half-cells.

Cell representation

The Daniell cell is written as:

Zn | Zn2+ ‖ Cu2+ | Cu

A single vertical line (or forward slash) separates the electrode from the electrolyte. The double line represents the salt bridge. Anode always on the left, cathode always on the right. Get this habit right, and the E°cell formula never trips you up.

In the Daniell cell:

  • Anode: Zn(s) → Zn2+ + 2e
  • Cathode: Cu2+ + 2e → Cu(s)

Electrons flow from anode to cathode through the external circuit.

6. Electrode Potential and the Standard Hydrogen Electrode

Electrode potential (E) is the tendency of an electrode to lose or gain electrons when it is in contact with a solution of its own ions.

Standard electrode potential (E°) is measured with the metal dipped in a 1 M solution of its ions at a specified temperature. For gases, the standard conditions are 1 atmosphere pressure and 1 M ion concentration.

Here is the conceptual problem: oxidation and reduction always occur together, so a single electrode’s absolute potential can never be measured. We need a reference — the Standard Hydrogen Electrode (SHE), also called the Normal Hydrogen Electrode (NHE).

SHE construction: hydrogen gas at 1 atm bubbled into 1 M HCl, over a foil of platinised platinum. Represented as Pt, H2(g) | H+(1 M), with its potential taken as zero at any specified temperature.

It is reversible with respect to H+ ions, working as an anode (H2 → 2H+ + 2e) or as a cathode (2H+ + 2e → H2) depending on the other half-cell.

Limitations of the SHE

This is a frequently asked short-answer question:

  • Difficult to set up and maintain — requires pure H2 at exactly 1 atmosphere pressure.
  • The platinum electrode is easily poisoned by traces of impurities in the gas or solution.
  • Maintaining exactly 1 M H+ concentration is experimentally difficult.
  • Cannot be used with strong oxidising or reducing agents that would react with hydrogen gas.

Because of these, secondary reference electrodes — the calomel electrode and the silver–silver chloride electrode, both calibrated against the SHE — are more commonly used in practice.

How the Zn and Cu potentials were found

Coupling a Zn electrode in 1 M ZnSO4 with the SHE gives an EMF of 0.76 V, with zinc as the negative electrode. Hence E°(Zn2+|Zn) = – 0.76 V.

Coupling a Cu electrode in 1 M CuSO4 with the SHE gives 0.34 V, with copper as the positive electrode (cathode), since Cu2+ is reduced more readily than H+. Hence E°(Cu2+|Cu) = + 0.34 V.

Copper is reduced in preference to hydrogen; zinc is oxidised in preference to hydrogen. That difference in sign is exactly what allows metals to be ranked in the electrochemical series.

Also remember: Reduction potential = – Oxidation potential. So the standard oxidation potential of Zn | Zn2+ is + 0.76 V.

7. The Electrochemical Series and Its Applications

Arranging electrodes in order of increasing standard reduction potential gives the electrochemical series. A selection of values at 298 K:

Reduction half reaction Standard reduction potential, E° (volts)
Li+ + e → Li – 3.05
K+ + e → K – 2.93
Ca2+ + 2e → Ca – 2.87
Na+ + e → Na – 2.71
Mg2+ + 2e → Mg – 2.37
Al3+ + 3e → Al – 1.66
Zn2+ + 2e → Zn – 0.76
Fe2+ + 2e → Fe – 0.44
Ni2+ + 2e → Ni – 0.25
Pb2+ + 2e → Pb – 0.13
2H+ + 2e → H2 0.00
Cu2+ + 2e → Cu + 0.34
I2 + 2e → 2I + 0.53
Fe3+ + e → Fe2+ + 0.77
Ag+ + e → Ag + 0.80
Br2 + 2e → 2Br + 1.08
O2(g) + 4H+(aq) + 4e → 2H2O + 1.23
Cl2 + 2e → 2Cl + 1.36
Au3+ + 3e → Au + 1.50
F2 + 2e → 2F + 2.87
The lower the value of standard reduction potential, the more reactive the metal.

Four applications of the electrochemical series

  1. Comparing oxidising and reducing powers — species at the top (very negative E°) are strong reducing agents; those at the bottom (very positive E°) are strong oxidising agents. F2 is the strongest oxidising agent in the list; Li the strongest reducing agent.
  2. Comparing the relative activities of metals.
  3. Predicting the feasibility of a redox reaction — the reaction is spontaneous if the species being reduced has the more positive standard reduction potential than the species being oxidised. Equivalently, E°cell must come out positive.
  4. Calculating the standard EMF of any cell.
cell = E°cathode – E°anode = E°right – E°left

8. Cell Potential, EMF and Potential Difference

Ecell = Ecathode – Eanode

The EMF of a cell depends on the nature of the reactants, the concentration of the solutions in the two half-cells, and the temperature.

EMF Potential Difference
Measured when no current flows in the circuit Measured under any conditions
Cannot be measured by an ordinary voltmeter (which draws current) Can be measured by a simple voltmeter
Maximum voltage obtainable from the cell Always less than the EMF
Constant for a given cell Depends on the strength of current flowing
Responsible for the flow of steady current Is not

9. The Nernst Equation

Standard potentials assume 1 M concentration at 298 K. Real cells rarely oblige. The Nernst equation tells us what happens otherwise.

For a single electrode

For Mn+ + ne → M:

E = E° – (RT / nF) ln ([M] / [Mn+])

where E is the electrode potential at the given concentration, E° the standard electrode potential, R the gas constant, T the temperature in kelvin, F the faraday, and n the number of electrons involved in the electrode reaction.

Since the concentration of a pure solid or liquid is taken as unity, [M] = 1:

E = E° – (2.303 RT / nF) log (1 / [Mn+])

Substituting R = 8.314 J K–1 mol–1, F = 96500 C and T = 298 K:

E = E° – (0.0591 / n) log (1 / [Mn+])

For a cell reaction

For the general reaction aA + bB → xX + yY:

Ecell = E°cell – (0.0591 / n) log ( [X]x[Y]y / [A]a[B]b )

Worked example — the Daniell cell. For Zn + Cu2+ → Zn2+ + Cu, n = 2, and with [Zn] = [Cu] = 1:

Ecell = E°cell – (0.0591 / 2) log ( [Zn2+] / [Cu2+] )

Second example. For 2Cr + 3Fe2+ → 2Cr3+ + 3Fe, n = 6:

Ecell = E°cell – (0.0591 / 6) log ( [Cr3+]2 / [Fe2+]3 )
Note how the coefficients in the balanced equation become the powers, and how n is 6 — not 3, and not 2. Finding n correctly is where most Nernst numericals are won or lost.

For gases, partial pressure in atmospheres replaces concentration.

10. Equilibrium Constant and Gibbs Free Energy

Kc from the Nernst equation

As a Daniell cell runs, [Cu2+] falls and [Zn2+] rises. Eventually the two electrode potentials become equal, the current stops flowing, and Ecell = 0. The cell reaction has reached equilibrium. Substituting Ecell = 0:

cell = (0.0591 / n) log Kc   (at 298 K)

So the standard EMF of a cell directly gives its equilibrium constant.

Free energy

In an electrochemical cell, the electrical work done by the cell equals the decrease in free energy of the system. Since one mole of electrons carries one faraday, n moles carry nF:

– ΔG = nFEcell     – ΔG° = nFE°cell

Combining this with the expression above:

ΔG° = – 2.303 RT log Kc

Predicting spontaneity — the table to memorise

cell ΔG° Conclusion
Positive Negative Forward reaction is spontaneous
Negative Positive Forward reaction is non-spontaneous (reverse is spontaneous)
Zero Zero Reaction is at equilibrium

11. Variation of Molar Conductivity with Concentration

Strong electrolytes

Molar conductivity varies with concentration according to Kohlrausch’s equation:

Λm = Λ°m – b√c

where Λ°m is the molar conductivity at infinite dilution and b is a constant depending on the nature of the solvent and the temperature. A plot of Λm against √c is linear at low concentration and deviates from linearity at higher concentrations. Extrapolating this line to c = 0 gives Λ°m directly.

Weak electrolytes

Weak electrolytes furnish far fewer ions, so their conductance is much lower than that of a strong electrolyte at the same concentration. For CH3COOH, molar conductivity rises steeply on dilution — especially near infinite dilution — because dilution increases ionisation and therefore the number of ions in solution. But the curve runs almost parallel to the Λm axis and never reaches a limiting value, so it cannot be extrapolated. Λ°m for a weak electrolyte must be obtained indirectly.

12. Kohlrausch’s Law of Independent Migration of Ions

The molar conductivity of an electrolyte at infinite dilution is the sum of the molar ionic conductivities of the cations and the anions, each multiplied by the number of ions present in one formula unit of the electrolyte.

For an electrolyte AxBy:

Λ°m = x λ°m(Ay+) + y λ°m(Bx–)

Application 1 — Λ°m for a weak electrolyte

For acetic acid, write the three strong-electrolyte equations:

  • Λ°m(KCl) = λ°(K+) + λ°(Cl)
  • Λ°m(CH3COOK) = λ°(CH3COO) + λ°(K+)
  • Λ°m(HCl) = λ°(H+) + λ°(Cl)

Then:

Λ°m(CH3COOH) = Λ°m(CH3COOK) + Λ°m(HCl) – Λ°m(KCl)

The K+ and Cl terms cancel, leaving exactly λ°(CH3COO) + λ°(H+). Elegant, and very examinable.

Application 2 — degree of dissociation

α = Λcm / Λ°m

This gives the fraction of ions actually available at concentration c out of the total number possible at infinite dilution. It holds good only for weak electrolytes.

13. Batteries and Fuel Cells

A battery is a galvanic cell, or a series of cells, designed to be self-contained.

Lead storage battery

Six cells in series; lead anode, 38% H2SO4, PbO2 cathode.

Pb + PbO2 + 4H+ + 2SO42– → 2PbSO4 + 2H2O

Rechargeable, because both reactions are reversible. Its state of charge can be checked by testing the density of the electrolyte — H2SO4 is progressively replaced by water as the battery discharges.

Dry cell

Zn can as anode; moist paste of MnO2, NH4Cl and ZnCl2 in starch; carbon rod cathode.

Zn + 2NH4+ + 2MnO2 → Zn2+ + Mn2O3 + 2NH3 + H2O

Alkaline battery

NH4Cl replaced by KOH or NaOH. The Zn anode corrodes less, and the cell voltage stays more constant because all species in the net reaction are condensed phases.

Zn + 2MnO2 → ZnO + Mn2O3

Mercury battery

Zn/Hg amalgam anode, paste of KOH, Zn(OH)2 and HgO, steel cathode.

Zn(Hg) + HgO → ZnO + Hg

Voltage remains constant until the reactants are spent, again because all species are in condensed phases.

Ni-Cad battery

Rechargeable, since both reactions are reversible.

Cd + NiO2 + 2H2O → Cd(OH)2 + Ni(OH)2

Fuel cell

A galvanic cell in which the reactants are supplied continuously. In the H2–O2 fuel cell, porous carbon electrodes with Ni and NiO catalysts sit in hot KOH solution; E° = 1.23 V.

  • Anode: 2H2(g) → 4H+(aq) + 4e
  • Cathode: O2(g) + 4H+(aq) + 4e → 2H2O(l)
Net: 2H2(g) + O2(g) → 2H2O(l)

The steam generated is condensed and used as drinking water — which is why fuel cells were used on space missions.

14. Corrosion

Corrosion is the undesired oxidation of metals to oxides and other compounds. When the metal is iron, we call the process rusting.

The surface of a metal acts as a tiny voltaic cell wherever there is a difference in potential between two points — caused by water vapour, impurities in the metal, or stressed regions created during machining.

Oxidation half-reaction: Fe(s) → Fe2+(aq) + 2e    E°ox = 0.44 V

The reduction half-reaction depends on the pH and on the availability of oxygen. Under normal conditions, water in contact with air carries enough dissolved oxygen for:

O2(g) + 2H2O + 4e → 4OH(aq)    E°red = 0.40 V (0.81 V at pH 7)

Combining the two gives the net rusting reaction:

2Fe(s) + O2(g) + 2H2O → 2Fe(OH)2(s)

which is further oxidised:

4Fe(OH)2(s) + O2(g) + 2H2O → 4Fe(OH)3(s)

Fe(OH)3 is an idealised formula, often written Fe2O3·3H2O. Losing variable amounts of water gives the familiar rust, Fe2O3(H2O)x.

Methods of preventing corrosion

  • Plating with an inert metal such as chromium — but only if the plating is free of cracks. Tin cans work this way; once scratched, however, rusting is rapid, with iron acting as the anode and tin as the cathode.
  • Sacrificial protection — coating with zinc, which oxidises more readily than iron and is “sacrificed”. Zn acts as a sacrificial anode, so no rusting occurs even if the coating is scratched. This is galvanisation.
  • Self-protective coatings — aluminium forms a stable Al2O3 layer; copper forms a green CuCO3 patina.
  • Protective coatings such as the paints used on titanium alloys.
  • Annealing — heating followed by slow cooling — slows down the rate of corrosion.
Note the contrast worth remembering: tin protects only while intact; zinc protects even when scratched.

What speeds corrosion up

Salt (ocean spray, road de-icing salt), acid rain, and regions where the metal has been worked or stressed — the head or tip of a nail, or the point where a nail is bent.

15. Ten Mistakes That Cost Marks Every Year

  1. Writing E°cell = E°anode – E°cathode. It is cathode minus anode.
  2. Getting n wrong in the Nernst equation. Use the number of electrons in the balanced cell reaction.
  3. Confusing κ and Λm — and, worse, their units. κ is per cm; Λm is cm2 per mole.
  4. Forgetting the factor of 1000 in Λm = κ × 1000 / Molarity.
  5. Applying α = Λcm / Λ°m to strong electrolytes. It is valid only for weak ones.
  6. Claiming Λ°m of a weak electrolyte can be found by extrapolation. It cannot — use Kohlrausch’s law.
  7. Saying “conductivity increases on dilution.” κ decreases on dilution (fewer ions per cm3); Λm increases. Two different quantities, two opposite trends.
  8. Saying electrons flow through the salt bridge. Ions do.
  9. Sign errors when converting between oxidation and reduction potentials.
  10. Writing log Q upside down — products belong in the numerator, reactants in the denominator.

16. Quick Formula Revision Sheet

Concept Formula
Resistance R = ρ l / A
Conductivity κ = 1/ρ = G × cell constant
Cell constant l / A  (cm–1)
Equivalent conductivity Λeq = κ × 1000 / Normality
Molar conductivity Λm = κ × 1000 / Molarity
Faraday’s first law W = Z I t
Electrochemical equivalent Z = Equivalent weight / 96500
Faraday’s second law W1 / W2 = E1 / E2
Faraday’s constant F = 96500 C mol–1
Standard EMF cell = E°cathode – E°anode
Nernst equation (electrode) E = E° – (0.0591/n) log (1 / [Mn+])
Nernst equation (cell) Ecell = E°cell – (0.0591/n) log Q
Equilibrium constant cell = (0.0591/n) log Kc
Free energy ΔG = – nFEcell ; ΔG° = – nFE°cell
Free energy and Kc ΔG° = – 2.303 RT log Kc
Kohlrausch’s equation Λm = Λ°m – b√c
Kohlrausch’s law Λ°m(AxBy) = xλ°+ + yλ°
Degree of dissociation α = Λcm / Λ°m
Useful constants: F = 96500 C mol–1  ·  R = 8.314 J K–1 mol–1  ·  at 298 K, 2.303 RT / F = 0.0591 V

17. Test Yourself

  1. Why does electrolytic conductance increase with temperature while metallic conductance decreases?
  2. A conductivity cell has a cell constant of 1.25 cm–1. If the conductance of a 0.1 M solution is 2.5 × 10–3 S, calculate κ and Λm.
  3. State two limitations of the standard hydrogen electrode and name one secondary reference electrode.
  4. Calculate E°cell for the cell Zn | Zn2+(1 M) ‖ Cu2+(1 M) | Cu, and predict whether the reaction is spontaneous.
  5. Write the Nernst equation for 2Cr + 3Fe2+ → 2Cr3+ + 3Fe and state the value of n.
  6. Why can Λ°m for acetic acid not be determined graphically? How is it determined?
  7. Explain why a scratched galvanised iron sheet still resists rusting, while a scratched tin can rusts rapidly.
  8. Given E°cell = 1.10 V for the Daniell cell, calculate ΔG° and Kc at 298 K. (n = 2)

Frequently Asked Questions

Is Electrochemistry a difficult chapter in ISC Class 12 Chemistry?

It is demanding rather than difficult. The chapter has few independent ideas — most of it flows from conductance and electrode potential. Students find it hard mainly because the formulas look similar, so errors come from picking the wrong one rather than from not knowing the concept.

What is the difference between conductivity and molar conductivity?

Conductivity (κ) is the conductance of a solution held between electrodes 1 cm apart with 1 cm2 area — it measures conduction per unit volume. Molar conductivity (Λm) is the conductance of all the ions from one mole of electrolyte. On dilution, κ decreases, but Λm increases.

Why is the Nernst equation important?

Standard electrode potentials only apply at 1 M concentration and 298 K. The Nernst equation lets you calculate the actual electrode potential or cell EMF at any concentration and temperature, and it is also the route to the equilibrium constant of the cell reaction.

Where does the value 0.0591 in the Nernst equation come from?

It is 2.303 RT / F evaluated at 298 K, with R = 8.314 J K–1 mol–1 and F = 96500 C mol–1. It is valid only at 298 K — at any other temperature you must use the full 2.303 RT / nF form.

Why can the molar conductivity of a weak electrolyte at infinite dilution not be found graphically?

The plot of Λm against √c for a weak electrolyte is a steep curve that runs nearly parallel to the Λm axis near infinite dilution, so it cannot be extrapolated reliably to c = 0. Λ°m is instead calculated using Kohlrausch’s law from strong electrolytes.

What is the main difference between a galvanic cell and an electrolytic cell?

A galvanic cell converts chemical energy into electrical energy through a spontaneous redox reaction. An electrolytic cell does the reverse: electrical energy is supplied from outside to drive a non-spontaneous redox reaction.

Final Thought

If you take one thing from this chapter, take this: electrochemistry is one story told four ways.cell tells you whether a reaction will go. ΔG° tells you the same thing in energy units. Kc tells you how far it will go. And the Nernst equation tells you what happens when conditions are not standard. They are all connected by two short equations — ΔG° = – nFE°cell and E°cell = (0.0591/n) log Kc.

Learn the connections rather than the individual formulas, and the numericals will start solving themselves.